2a^2-11a+9=0

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Solution for 2a^2-11a+9=0 equation: 



2a^2-11a+9=0

a = 2; b = -11; c = +9;
Δ = b2-4ac
Δ = -112-4·2·9
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-7}{2*2}=\frac{4}{4}
=1
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+7}{2*2}=\frac{18}{4}
=4+1/2
$

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